template specialization for static member functions; howto?

Question

I am trying to implement a template function with handles void differently using template specialization.

The following code gives me an \"Explicit specialization in non

Answer 1

You can declare the explicit specialisation in the same way you'd define a member function outside of its class:

class A
{
public:
  template 
  static void foo () {}
};

template <>
void A::foo ()
{
}