find the elapsed time between two dates in oracle sql

Question

i need to find the difference between the time in the format hh:mm:ss

select msglog.id,max(msglog.timestamp) enddate,
   min(msglog.timestamp) startdate,
   en         


        

Answer 1

Date arithmetic in Oracle results in a number expressed in days. So, to convert to hours, you would multiply by 24 and then trunc to get an integral number:

trunc(24 * (enddate - startdate))

To get minutes, convert the days value to minutes and mod() that with 60:

mod(trunc(24 * 60 * (enddate - startdate)), 60)

For seconds, again convert days to seconds and mod() that with 60:

mod(trunc(24 * 60 * 60 * (enddate - startdate)), 60)

Now you can put these together to get the string value you need.