How to create a type excluding instance methods from a class in typescript?

Question

Given a class, containing both properties and methods, I\'d like to derive a type that just contains its properties.

For example, if I define a class as follow:

Answer 1

Given a class, containing both properties and methods, I'd like to derive a type that just contains its properties.

From your example, it seems like you want the result to contain only fields (as opposed to only properties). Here is a type that picks out the fields from an object or class instance.

type DataPropertyNames = {
  [K in keyof T]: T[K] extends Function ? never : K;
}[keyof T];

type DataPropertiesOnly = {
  [P in DataPropertyNames]: T[P] extends object ? DTO : T[P]
};

export type DTO = DataPropertiesOnly;

I have used the acronym DTO to mean Data Transfer Object. Thank you to l00ser2410656 for this playground demo.