this.getClass().getResource(“”).getPath() returns an incorrect path

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灰色年华
灰色年华 2021-02-05 17:45

I am currently making a small simple Java program for my Computer Science Final, which needs to get the path of the current running class. The class files are in the C:\\2013\\g

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  •  没有蜡笔的小新
    2021-02-05 18:09

    If you want to load a file in the same path as the code then I suggest you put it in the same root folder as the code and not the same path as the class.

    Reason : class can be inside a jar, data file can be put in same jar but its more difficult to edit and update then.

    Also suggest you see the preferences class suggested in comments : http://www.javacodegeeks.com/2011/09/use-javautilprefspreferences-instead-of.html though in some cases I think its okay to have your own data/ excel/csv/ java.util.Properties file

    Not sure about why it is working in eclipse but I would suggest you focus on running it from a command prompt/ terminal as that is the 'real mode' when it goes live

    You could just ask for your class

        String s = getClass().getName();
        int i = s.lastIndexOf(".");
        if(i > -1) s = s.substring(i + 1);
        s = s + ".class";
        System.out.println("name " +s);
        Object testPath = this.getClass().getResource(s);
        System.out.println(testPath);
    

    This will give you

    name TstPath.class file:/java/Projects/tests3b/build/classes/s/TstPath.class

    Which is my eclipse build path ...

    need to parse this to get the path where the class was loaded.

    Remember:

    1. App could be started from elsewhere
    2. class can be in jar then path will be different (will point to a jar and file inside that
    3. classpaths can be many at runtime and point 1
    4. a class might be made at runtime via network/ Proxy / injection etc and thus not have a file source, so this is not a generic solution.
    5. think what you want to acheive at a higher level and post that question. meaning why do you want this path?
    6. do you want the app path :-

      File f = new File("./");
      f.getCanonicalPath();//...

    So an app can be started from folder c:\app1\run\

    The jar could be at c:\app1\libsMain\myapp.jar

    and a helper jar could be at c:\commonlibs\set1

    So this will only tell you where the JVM found your class, that may or maynot be what you need.

    if inside a jar will give you some thing like this in unix or windows

    jar:file:c:\app\my.jar!/s/TstPath.class

    If package is s and class is TstPath, you can be sure this will work as the class has to be there ...

    now to parse this you can look for your class name and remove / or \ till you get path you want. String lastIndexOf will help

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