So I have this regex:
(^(\\s+)?(?P(\\w)(\\d{7}))((01f\\.foo)|(\\.bar|\\.goo\\.moo\\.roo))$|(^(\\s+)?(?PR1_\\d{6}_\\d{6}_)((01f\\.foo)|(\
No, you can't have two groups of the same name, this would somehow defy the purpose, wouldn't it?
What you probably really want is this:
^\s*(?P\w\d{7}|R1_(?:\d{6}_){2})(01f\.foo|\.(?:bar|goo|moo|roo))$
I refactored your regex as far as possible. I made the following assumptions:
You want to (correct me if I'm wrong):
"R1_", and two times (6 digits + "_")"01f.foo" or"." and ("bar" or "goo" or "moo" or "roo")You could also have meant:
^\s*(?P\w\d{7}01f|R1_(?:\d{6}_){2})\.(?:foo|bar|goo|moo|roo)$
Which is:
"R1_", and two times (6 digits + "_")"foo", "bar", "goo", "moo" or "roo"