Comparing doubles in Java gives odd results

Question

I really can\'get my head around why the following happens:

Double d = 0.0;
System.out.println(d == 0); // is true
System.out.println(d.equals(0)); // is false ?         


        

Answer 1

d.equals(0) : 0 is an int. The Double.equals() code will return true only for Double objects.