Call a void* as a function without declaring a function pointer

Question

I\'ve searched but couldn\'t find any results (my terminology may be off) so forgive me if this has been asked before.

I was wondering if there is an easy way to call a

Answer 1

Your cast should be:

((void (*)(void)) ptr)();

In general, this can be made simpler by creating a typedef for the function pointer type:

typedef void (*func_type)(void);
((func_type) ptr)();

I should, however, point out that casting an ordinary pointer (pointer to object) to or from a function pointer is not strictly legal in standard C (although it is a common extension).