How to display row numbers in a ListView?

Question

The obvious solution would be to have a row number property on a ModelView element, but the drawback is that you have to re-generate those when you add records or change sor

Answer 1

Here is another way, including code comments that will help you understand how it works.

public class Person
{
    private string name;
    private int age;
    //Public Properties ....
}

public partial class MainWindow : Window
{

    List personList;
    public MainWindow()
    {
        InitializeComponent();

        personList= new List();
        personList.Add(new Person() { Name= "Adam", Agen= 25});
        personList.Add(new Person() { Name= "Peter", Agen= 20});

        lstvwPerson.ItemsSource = personList;
//After updates to the list use lstvwPerson.Items.Refresh();
    }
}

The XML

RelativeSource is used in particular binding cases when we try to bind a property of a given object to another property of the object itself [1].

Using Mode=FindAncestor we can traverse the hierarchy layers and get a specified element, for example the ListViewItem (we could even grab the GridViewColumn). If you have two ListViewItem elements you can specify which you want with "AncestorLevel = x".

Path: Here I simply take the content of the ListViewItem (which is my object "Person").

Converter Since I want to display row numbers in my Number column and not the object Person I need to create a Converter class which can somehow transform my Person object to a corresponding number row. But its not possible, I just wanted to show that the Path goes to the converter. Deleting the Path will send the ListViewItem to the Converter.

ConverterParameter Specify a parameter you want to pass to the IValueConverter class. Here you can send the state if you want the row number to start at 0,1,100 or whatever.

public class IndexConverter : IValueConverter
{
    public object Convert(object value, Type TargetType, object parameter, System.Globalization.CultureInfo culture)
    {
        //Get the ListViewItem from Value remember we deleted Path, so the value is an object of ListViewItem and not Person
        ListViewItem lvi = (ListViewItem)value;
        //Get lvi's container (listview)
        var listView = ItemsControl.ItemsControlFromItemContainer(lvi) as ListView;

        //Find out the position for the Person obj in the ListView
//we can get the Person object from lvi.Content
        // Of course you can do as in the accepted answer instead!
        // I just think this is easier to understand for a beginner.
        int index = listView.Items.IndexOf(lvi.Content);

        //Convert your XML parameter value of 1 to an int.
        int startingIndex = System.Convert.ToInt32(parameter);

        return index + startingIndex;
    }

    public object ConvertBack(object value, Type targetType, object parameter, System.Globalization.CultureInfo culture)
    {
        throw new NotImplementedException();
    }
}