jQuery (almost) equivalent of PHP's strip_tags()

Question

Is there a jQuery version of this function?

string strip_tags( string $str [, string $allowable_tags ] )

stri

Answer 1

Even if this is an old thread i think it could be useful for those who are still looking for an answer.

The Locutus.io function seems to be the best solution:

function strip_tags (input, allowed) {
      allowed = (((allowed || '') + '').toLowerCase().match(/<[a-z][a-z0-9]*>/g) || []).join('')
      var tags = /<\/?([a-z][a-z0-9]*)\b[^>]*>/gi
      var commentsAndPhpTags = /|<\?(?:php)?[\s\S]*?\?>/gi
      return input.replace(commentsAndPhpTags, '').replace(tags, function ($0, $1) {
        return allowed.indexOf('<' + $1.toLowerCase() + '>') > -1 ? $0 : ''
      })
}

Example 1:

strip_tags('
Kevin
 
van Zonneveld', '')

returns 1: 'Kevin van Zonneveld'

Example 2:

strip_tags('
Kevin van Zonneveld
', '
')

returns 2: '

Kevin van Zonneveld

'

Example 3:

strip_tags("Kevin van Zonneveld", "")

returns 3: "Kevin van Zonneveld"

Example 4:

strip_tags('1 < 5 5 > 1')

returns 4: '1 < 5 5 > 1'

Example 5:

strip_tags('1 
 1')

returns 5: '1 1'

Example 6:

strip_tags('1 
 1', '
')

returns 6: '1
1'

Example 7:

strip_tags('1 
 1', '

')

returns 7: '1
1'