What's the difference between numpy.take and numpy.choose?

Question

It seems that numpy.take(array, indices) and numpy.choose(indices, array) return the same thing: a subset of array indexed by indice

Answer 1

They are certainly not equivalent, as you can see by giving the same arguments (switched) to both methods:

>>> a = np.array([[1, 2, 3, 4], 
                  [5, 6, 7, 8], 
                  [9, 10, 11, 12], 
                  [13, 14, 15, 16]])
>>> np.choose([0, 2, 1, 3], a)
array([ 1, 10,  7, 16]) # one from each row
>>> np.take(a, [0, 2, 1, 3])
array([1, 3, 2, 4]) # all from same row

I suggest you read the documentation on take and choose.