How do you unwrap Swift optionals?

Question

How do you properly unwrap both normal and implicit optionals?

There seems to be confusion in this topic and I would just like to have a reference for all of the way

Answer 1

An optional type means that the variable might be nil.

Example:

var myString: Int? = 55
myString = nil

The question mark indicates it might have nil value.

But if you state like this:

var myString : Int = 55
myString = nil

It will show error.

Now to retrieve the value you need to unwrap it:

print(myString!)

But if you want to unwrap automatically:

var myString: Int! = 55

Then:

print(myString)

No need to unwrap. Hope it will help.