When using == for a primitive and a boxed value, is autoboxing done, or is unboxing done

Question

The following code compiles (with Java 8):

Integer i1 = 1000;
int i2 = 1000;
boolean compared = (i1 == i2);

But what does it do?

Un

Answer 1

Explanation

1. When two primitive values are compared using == operator autoboxing does not take place.

2. When two objects are compared using == operator autoboxing plays role.

3. When mixed combination is used that is it contains an Object and primitive type and comparison is done using == operator unboxing happens on the Object and is converted to primitive type.

Please go through the below link which will help you get understand detailed about auto-boxing with suitable example.

Refer Link : http://javarevisited.blogspot.in/2012/07/auto-boxing-and-unboxing-in-java-be.html