When using == for a primitive and a boxed value, is autoboxing done, or is unboxing done

Question

The following code compiles (with Java 8):

Integer i1 = 1000;
int i2 = 1000;
boolean compared = (i1 == i2);

But what does it do?

Un

Answer 1

Lets do some examples :

Case -1 :

       public static void main(String[] args) {
            Integer i1 = 1000;
            int i2 = 1000;
            boolean compared = (i1 == i2);
            System.out.println(compared);
        }

Byte code :

....
        16: if_icmpne     23 // comparing 2 integers
....

Case -2 :

public static void main(String[] args) {
    Integer i1 = 1000;
    Integer i2 = 1000;
    //int i2 = 1000;
    boolean compared = (i1 == i2);
    System.out.println(compared);
}

Bytecode :

...
     16: if_acmpne     23 // comparing references
....

So, in case of comparison of Integer and int with == the Integer is unboxed to an int and then comparison happens.

In case of comparing 2 Integers, the references of 2 Integers are compared.