I\'ve been crawling in the web for about 5 hours now and couldn\'t find a solution for my problem:
My company is developing an educational game and I\'m writing an autou
You could take advantage of TTL. With a TTL of 1 the packet won't be able to make it to the internet:
private static bool IsLanIP(IPAddress address)
{
var ping = new Ping();
var rep = ping.Send(address, 100, new byte[] { 1 }, new PingOptions()
{
DontFragment = true,
Ttl = 1
});
return rep.Status != IPStatus.TtlExpired && rep.Status != IPStatus.TimedOut && rep.Status != IPStatus.TimeExceeded;
}
However, remember that it is called an IPv4 mask for a reason - you can use it as one (so here is your algorithmic solution):
private static bool IsLanIP(IPAddress address)
{
var interfaces = NetworkInterface.GetAllNetworkInterfaces();
foreach (var iface in interfaces)
{
var properties = iface.GetIPProperties();
foreach (var ifAddr in properties.UnicastAddresses)
{
if (ifAddr.IPv4Mask != null &&
ifAddr.Address.AddressFamily == AddressFamily.InterNetwork &&
CheckMask(ifAddr.Address, ifAddr.IPv4Mask, address))
return true;
}
}
return false;
}
private static bool CheckMask(IPAddress address, IPAddress mask, IPAddress target)
{
if (mask == null)
return false;
var ba = address.GetAddressBytes();
var bm = mask.GetAddressBytes();
var bb = target.GetAddressBytes();
if (ba.Length != bm.Length || bm.Length != bb.Length)
return false;
for (var i = 0; i < ba.Length; i++)
{
int m = bm[i];
int a = ba[i] & m;
int b = bb[i] & m;
if (a != b)
return false;
}
return true;
}