How to parse a URL?

Question

If there is one thing I just cant get my head around, it\'s regex.

So after a lot of searching I finally found this one that suits my needs:

function         


        

Answer 1

You just need to modify your regex a bit. For example:

var aaaa="http://www.somesite.se/blah/sdgsdgsdgs";
var m = aaaa.match(/^[^:]*:\/\/([^\/]+)(\/.*)$/);

m will then contain the following parts:

["http://www.somesite.se/blah/sdgsdgsdgs", "www.somesite.se", "/blah/sdgsdgsdgs"]

Here is the same example, but modified so that it will split out the "www." part. I think the regular expression should be written so that the match will work whether or not you you have the "www." part. So check this out:

var aaaa="http://www.somesite.se/blah/sdgsdgsdgs";
var m = aaaa.match(/^[^:]*:\/\/(www\.)?([^\/]+)(\/.*)$/);

m will then contain the following parts:

["http://www.somesite.se/blah/sdgsdgsdgs", "www.", "somesite.se", "/blah/sdgsdgsdgs"]

Now check out the same regular expression but with a url that does not start with "www.":

var bbbb="http://somesite.se/blah/sdgsdgsdgs";
var m = .match(/^[^:]*:\/\/(www\.)?([^\/]+)(\/.*)$/);

Now your match looks like this:

["http://somesite.se/blah/sdgsdgsdgs", undefined, "somesite.se", "/blah/sdgsdgsdgs"]

So as you can see it will do the right thing in both cases.