Where is `%p` useful with printf?

Question

After all, both these statements do the same thing...

int a = 10;
int *b = &a;
printf(\"%p\\n\",b);
printf(\"%08X\\n\",b);

For example

Answer 1

The size of the pointer may be something different than that of int. Also an implementation could produce better than simple hex value representation of the address when you use %p.