I\'m trying to throw a custom error with my \"CustomError\" class name printed in the console instead of \"Error\", with no success:
class CustomError extend
As of TypeScript 2.2 it can be done via new.target.prototype.
https://www.typescriptlang.org/docs/handbook/release-notes/typescript-2-2.html#example
class CustomError extends Error {
constructor(message?: string) {
super(message); // 'Error' breaks prototype chain here
this.name = 'CustomError';
Object.setPrototypeOf(this, new.target.prototype); // restore prototype chain
}
}