Member pointer to array element

Question

It\'s possible to define a pointer to a member and using this later on:

struct foo
{
  int a;
  int b[2];
};


int main()
{

  foo bar;
  int foo::*          


        

Answer 1

I'm not sure if this will work for you or not, but I wanted to do a similar thing and got around it by approaching the problem from another direction. In my class I had several objects that I wanted to be accessible via a named identifier or iterated over in a loop. Instead of creating member pointers to the objects somewhere in the array, I simply declared all of the objects individually and created a static array of member pointers to the objects.

Like so:

struct obj
{
    int somestuff;
    double someotherstuff;
};

class foo
{
  public:
    obj apples;
    obj bananas;
    obj oranges;

    static obj foo::* fruit[3];

    void bar();
};

obj foo::* foo::fruit[3] = { &foo::apples, &foo::bananas, &foo::oranges };


void foo::bar()
{
    apples.somestuff = 0;
    (this->*(fruit[0])).somestuff = 5;
    if( apples.somestuff != 5 )
    {
        // fail!
    }
    else
    {
        // success!
    }
}



int main()
{
    foo blee;
    blee.bar();
    return 0;
}

It seems to work for me. I hope that helps.