String s = new String(“xyz”). How many objects has been made after this line of code execute?

Question

The commonly agreed answer to this interview question is that two objects are created by the code. But I don\'t think so; I wrote some code to confirm.

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Answer 1

public String(String original) {
    int size = original.count;
    char[] originalValue = original.value;
    char[] v;
    if (originalValue.length > size) {
        // The array representing the String is bigger than the new
        // String itself.  Perhaps this constructor is being called
        // in order to trim the baggage, so make a copy of the array.
        int off = original.offset;
        v = Arrays.copyOfRange(originalValue, off, off+size);
    } else {
        // The array representing the String is the same
        // size as the String, so no point in making a copy.
        v = originalValue;
    }
    this.offset = 0;
    this.count = size;
    this.value = v;
}

If we see the code , we can see it will just create a char[] and it will get copied every time with same content get instantiated and yes it will store data in String Constant Pool . 1)Will take from SCP String s1 = "a" String s2 = "a"; 2)Creates a new object String s3 = new String("a"); Curiosity , New Object String s2=new String("a"); In all above code same char[] will get copied.i:e char[] value You can check here