How to paramaterize Int as Ordered in scala

Question

I have a class with a parameterized type that I want to do comparison operators on. I assmue I need to use the Ordered trait to achieve this but the compiler doesn\'t like my us

Answer 1

This occurs because Int is not a subclass of Ordered[Int] (see here why).

However, there is an implicit coercion from Int to RichInt which is a subclass of Ordered[Int], but it isn't triggered for lower bounds. Use <% (view bounds) instead which will consider implicit coercions:

class Test[T <% Ordered[T]]