问题
how to convert string to integer??
for ex:
- "5328764",to int base 10
- "AB3F3A", to int base 16
any code will be helpfull
回答1:
Assuming arbitrary base (not 16, 10, 8, 2):
In C (C++), use strtol
return strtol("AB3F3A", NULL, 16);
In Javascript, use parseInt
.
return parseInt("AB3F3A", 16);
In Python, use int(string, base)
.
return int("AB3F3A", 16)
In Java, use Integer.parseInt (thanks Michael.)
return Integer.parseInt("AB3F3A", 16);
In PHP, use base_convert.
return intval(base_convert('AB3F3A', 16, 10));
In Ruby, use to_i
"AB3F3A".to_i(16)
In C#, write one yourself.
回答2:
in C#, i think it is: Convert.ToInt64(value, base) and the base must be 2, 8, 10, or 16
回答3:
9999 is really 9000 + 900 + 90 + 9 So, start at the right hand side of the string, and pick off the numbers one at a time. Each character number has an ASCII code, which can be translated to the number, and multiplied by the appropriate amount.
回答4:
Two functions in java, in both directions: "code" parameter represent the numerical system: "01" for base 2, "0123456789" for base 10, "0123456789abcdef" for hexdecimal and so on...
public String convert(long num, String code) {
final int base = code.length();
String text = "";
while (num > 0) {
text = code.charAt((int) (num%base)) + text;
num /= base;
}
return text;
}
public long toLong(String text, String code) {
final long base = code.length();
long num = 0;
long pow = 1;
int len = text.length();
for(int i = 0; i < len; i++) {
num += code.indexOf(text.charAt(len - i - 1)) * pow;
pow *= base;
}
return num;
}
println(convert(9223372036854775807L,"0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ"));
println(convert(9223372036854775807L,"0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ@=-+*/^%$#&()!?.,:;[]"));
println(toLong("Ns8T$87=uh","0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ@=-+*/^%$#&()!?.,:;[]"));```
in your example:
toLong("5328764", "0123456789") = 5328764
toLong("AB3F3A", "0123456789ABCDEF") = 11222842
来源:https://stackoverflow.com/questions/2633495/how-do-i-convert-a-string-version-of-a-number-in-an-arbitrary-base-to-an-integer