iota

问题 The following example defines a series of port numbers starting at 3333 using iota. package main import ( "fmt" ) const ( FirstPort = iota+3333 SecondPort ThirdPort ) func main() { hostAndPort := "localhost:"+fmt.Sprint(SecondPort) fmt.Printf("%s", hostAndPort ) // Output: // localhost:3334 } When combining hostname and ports, I'd like to avoid having to wrap the port constant in fmt.Sprint and simply write, for example, "localhost:"+SecondPort . Is there a way to use iota to define the port

问题 This question already has answers here : What does iota of std::iota stand for? (5 answers) Closed 6 years ago . C++11 introduced a function called iota. Which "Assigns to every element in the range [first,last) successive values of val, as if incremented with ++val after each element is written." Can someone explain what "iota" means here though? I looked up "iota" and it seems to have nothing to do with generating a range. 回答1: Quoting this non-authoritative, but nonetheless correct, wiki:

问题 This question already has answers here : What does iota of std::iota stand for? (5 answers) Closed 6 years ago . C++11 introduced a function called iota. Which "Assigns to every element in the range [first,last) successive values of val, as if incremented with ++val after each element is written." Can someone explain what "iota" means here though? I looked up "iota" and it seems to have nothing to do with generating a range. 回答1: Quoting this non-authoritative, but nonetheless correct, wiki:

问题 This question already has answers here : What does iota of std::iota stand for? (5 answers) Closed 6 years ago . C++11 introduced a function called iota. Which "Assigns to every element in the range [first,last) successive values of val, as if incremented with ++val after each element is written." Can someone explain what "iota" means here though? I looked up "iota" and it seems to have nothing to do with generating a range. 回答1: Quoting this non-authoritative, but nonetheless correct, wiki:

问题 This question already has answers here : What does iota of std::iota stand for? (5 answers) Closed 6 years ago . C++11 introduced a function called iota. Which "Assigns to every element in the range [first,last) successive values of val, as if incremented with ++val after each element is written." Can someone explain what "iota" means here though? I looked up "iota" and it seems to have nothing to do with generating a range. 回答1: Quoting this non-authoritative, but nonetheless correct, wiki:

问题 This question already has answers here : What does iota of std::iota stand for? (5 answers) Closed 6 years ago . C++11 introduced a function called iota. Which "Assigns to every element in the range [first,last) successive values of val, as if incremented with ++val after each element is written." Can someone explain what "iota" means here though? I looked up "iota" and it seems to have nothing to do with generating a range. 回答1: Quoting this non-authoritative, but nonetheless correct, wiki:

问题 Say I have next c program: #include <stdio.h> int main(int args, char* argv[]) { enum RC { APPLE=0, ORANGE, PEAR, BANANA=99, GRAPE }; printf("%d, %d, %d, %d, %d\n", APPLE, ORANGE, PEAR, BANANA, GRAPE); } The output is: 0, 1, 2, 99, 100 If in go, how can I use a more golang way to handle that? In fact, if I just want to skip some value. e.g. print 0, 1, 2, 5, 6 , then I can use next to skip some value, but here I need to skip 96 values... package main import "fmt" func main() { const ( APPLE =

问题 Iota is a ridiculously small "programming language" using only one combinator. I'm interested in understanding how it works, but it would be helpful to see the implementation in a language I'm familiar with. I found an implementation of the Iota programming language written in Scheme. I've been having a little trouble translating it to Haskell though. It's rather simple, but I'm relatively new to both Haskell and Scheme. How would you write an equivalent Iota implementation in Haskell? (let

问题 Iota is a ridiculously small "programming language" using only one combinator. I'm interested in understanding how it works, but it would be helpful to see the implementation in a language I'm familiar with. I found an implementation of the Iota programming language written in Scheme. I've been having a little trouble translating it to Haskell though. It's rather simple, but I'm relatively new to both Haskell and Scheme. How would you write an equivalent Iota implementation in Haskell? (let

问题 With C++11, the STL has now a std::iota function (see a reference). In contrast to std::fill_n , std::generate_n , there is no std::iota_n , however. What would be a good implementation for that? A direct loop (alternative 1) or delegation to std::generate_n with a simple lambda expression (alternative 2)? Alternative 1) template<class OutputIterator, class Size, class T> OutputIterator iota_n(OutputIterator first, Size n, T value) { while (n--) *first++ = value++; return first; } Alternative