conditional-statements

问题 I want to exclude participants from an analysis that are too old (age >90). Usually I would do it like that: df <- data.frame(age=c(1,10, 100), x= 1:3, y= 1:3) df[df$age > 90, ] <- NA I can't figure out how to do this with dplyr. If we want to replace one variable we can use library(dplyr) df <- data.frame(age=c(1,10, 100), x= 1:3, y= 1:3) df %>% mutate(age= replace(age, age> 90, NA)) So I thought I could use df %>% mutate_all(function(i) replace(i, age> 90, NA)) I also tried mutate_if and

问题 I want to exclude participants from an analysis that are too old (age >90). Usually I would do it like that: df <- data.frame(age=c(1,10, 100), x= 1:3, y= 1:3) df[df$age > 90, ] <- NA I can't figure out how to do this with dplyr. If we want to replace one variable we can use library(dplyr) df <- data.frame(age=c(1,10, 100), x= 1:3, y= 1:3) df %>% mutate(age= replace(age, age> 90, NA)) So I thought I could use df %>% mutate_all(function(i) replace(i, age> 90, NA)) I also tried mutate_if and

问题 I'm new to R and I've been trying to multiply and replace certain values in my data frame with no success. Basically, what I want to do is that when a value from my df (any column) is 0 < x < 1, multiplicate it by 10 and then replace that value with the result of this equation. A glimpse to my df just in case... 'data.frame': 404 obs. of 15 variables: $ D3: num 16.1 17.1 16.1 16.1 17.2 ... $ TH : num 9.9 8.6 9.7 7.7 7.6 7.6 8.7 9.8 9.8 7.7 ... $ D2 : num 33.3 29.3 30.3 29.3 33.3 ... $ D1 :

问题 I am trying to subset rows of a data set using a condition that's based on the previous row, whilst keeping the previous row in the subsetted data. This is essentially the same as the question here, but I am looking for a dplyr approach: Select specific rows based on previous row value (in the same column) I have taken the dplyr approach applied in the comments to that answer, but I am unable to figure out the last step of retaining the previous row. I can get the rows that support the

问题 I have two dataframes called users and purchases with thousands of datasets to each. Both have a feature called ID . My aim is to add a new column called buyer to the dataframe purchases , if the value of ID of purchases exists in ID of users . So the two dataframes look like this: users = data.frame("ID" = c(23432,75645,5465645,5656,6456)) purchases = data.frame("ID" = c(6456,4436,88945)) It should look like: 回答1: We can use %in% to compare the values and wrap as.integer to convert logical

问题 This question is a follow-up to Bash conditional based on exit code of command . I understand, and have made use of the accepted answer to that question: $ cat ./txt foo bar baz $ if ! grep -Fx bax txt &>/dev/null; then echo "not found"; fi not found $ But I can't figure out the syntax to pull off a seemingly simple twist to the premise: how can I write a conditional for a specific exit code of a command? This post pointed out that grep might fail with error code > 1; so I wanted to write the

问题 Is it possible, in typescript, to let a method accept Partial<Something> , in a way that Something 's sub-properties are all set to optional too? export interface ISomething { user: IUser; } export interface IUser { id: number; name: string; } export const myMethod = (something: Partial<ISomething>): void => {}; myMethod({ user: { id: 1, name: "" } }); //this works myMethod({ user: { id: 1 } }); //this doesn't (but I want this to work too) many thanks ;) 回答1: You are essentially looking for

问题 I want to find a way to replace consecutive same values into 0 at the beginning of each trial, but once the value has changed it should stop replacing and keep the value. It should occur every trials per subject. For example, first subject has multiple trials (1, 2, etc). At the beginning of each trial, there may be some consecutive rows with the same value (e.g., 1, 1, 1). For these values, I would like to replace them to 0. However, once the value has changed from 1 to 0, I want to keep the

问题 I want to find a way to replace consecutive same values into 0 at the beginning of each trial, but once the value has changed it should stop replacing and keep the value. It should occur every trials per subject. For example, first subject has multiple trials (1, 2, etc). At the beginning of each trial, there may be some consecutive rows with the same value (e.g., 1, 1, 1). For these values, I would like to replace them to 0. However, once the value has changed from 1 to 0, I want to keep the

问题 I already found out how to count cases based on two conditions: sum(dat2$happy > 7 & dat2$induction == 1) But do you know how I can include a range of values as a criterion? One out of many codes I tried: sum(dat2[dat2$happy > 4 & dat2$happy < 8] & dat2$induction == 2) Tank you so much! 来源： https://stackoverflow.com/questions/65923147/counting-cases-two-conditions-range-of-values