conditional-operator

Python: Why is np.where not working with two conditions?

时光怂恿深爱的人放手 提交于 2021-02-16 21:19:58
问题 I have the following data frame: >>> import pandas as pd >>> import numpy as np >>> df_test = pd.DataFrame({'id': [100, 101, 102, 103, 104], 'drive': ['4WD', None, '4WD', None, '2WD']}) >>> print(df_test) id drive 0 100 4WD 1 101 None 2 102 4WD 3 103 None 4 104 2WD And I would like to make a new column is_4x4 , that would be equal to 0, when drive is None , or drive is 2WD . In other cases, I would like the column to be equal to 1. I am using the following code, but the result is not as I

Python: Why is np.where not working with two conditions?

╄→尐↘猪︶ㄣ 提交于 2021-02-16 21:19:08
问题 I have the following data frame: >>> import pandas as pd >>> import numpy as np >>> df_test = pd.DataFrame({'id': [100, 101, 102, 103, 104], 'drive': ['4WD', None, '4WD', None, '2WD']}) >>> print(df_test) id drive 0 100 4WD 1 101 None 2 102 4WD 3 103 None 4 104 2WD And I would like to make a new column is_4x4 , that would be equal to 0, when drive is None , or drive is 2WD . In other cases, I would like the column to be equal to 1. I am using the following code, but the result is not as I

Testing if multiple objects are in a list using one “in” statement (Python) [duplicate]

那年仲夏 提交于 2021-02-16 16:10:19
问题 This question already has answers here : Closed 8 years ago . Possible Duplicate: Python Check if all of the following items is in a list So I want to test whether both word and word1 are in the list lst. Of course, I could write: if word in lst and word1 in lst: do x But I wondered if I could shorten that statement to something like: if (word and word1) in lst: do x Of course, that does not work, but is there anything effectively similar that will? I tried the following, but as you can see,

Testing if multiple objects are in a list using one “in” statement (Python) [duplicate]

本小妞迷上赌 提交于 2021-02-16 16:08:24
问题 This question already has answers here : Closed 8 years ago . Possible Duplicate: Python Check if all of the following items is in a list So I want to test whether both word and word1 are in the list lst. Of course, I could write: if word in lst and word1 in lst: do x But I wondered if I could shorten that statement to something like: if (word and word1) in lst: do x Of course, that does not work, but is there anything effectively similar that will? I tried the following, but as you can see,

C++, ternary operator and cout

倾然丶 夕夏残阳落幕 提交于 2021-02-05 09:32:44
问题 this code doesn't work int main(){ cout << 5 ? (5 ? 0 : 2) : 5; system("pause"); return 0; } this code works int main(){ cout << (5 ? (5 ? 0 : 2) : 5); system("pause"); return 0; } can't understand why? 回答1: cout << 5 ? (5 ? 0 : 2) : 5; is parsed as (cout << 5) ? (5 ? 0 : 2) : 5; 回答2: This is due to operator precedence rules. << has higher precedence than ? , so your first expression is parsed as: (cout << 5) ? (5 ? 0 : 2) : 5; Brackets are necessary in this case to get the parse you want. 来源

What is the difference between using '&&' and '||' over a ternary operator ('?' and ':')?

岁酱吖の 提交于 2021-01-19 22:13:09
问题 In JavaScript, what is the difference between using true ? 'Hello' : 'Goodbye' //Evaluates to "Hello" false ? 'Hello' : 'Goodbye' //Evaluates to "Goodbye" and true && 'Hello' || 'Goodbye' //Evaluates to "Hello" false && 'Hello' || 'Goodbye' //Evaluates to "Goodbye" 回答1: These are two different concepts that happen to give you the same answer. The first example uses the ternary operator and its result depends only on the first operand (in your example true / false ): true ? 'Hello' : 'Goodbye'

PHP DOMDocument : How to parse custom XML/RSS tag names with COLONS?

安稳与你 提交于 2021-01-01 07:10:25
问题 I have the below RSS to parse, something like: <?xml version="1.0" encoding="utf-8"?> <rss xmlns:x-wr="http://www.w3.org/2002/12/cal/prod/Apple_Comp_628d9d8459c556fa#" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:x-example="http://www.example.com/rss/x-example" xmlns:x-microsoft="http://schemas.microsoft.com/x-microsoft" xmlns:xCal="urn:ietf:params:xml:ns:xcal" version="2.0"> <channel> <item> <title>About Apples</title> <author>David

java conditional operator and different types

≯℡__Kan透↙ 提交于 2020-11-25 02:17:27
问题 I have two methods in the Item Class: public void setValue(String v); public void setValue(Double v); and I want to use Conditional Operator to setVAlue in another class: String str = ... Double dbl = ... item.setValue((condition) ? str : dbl); but compiler says: cannot find symbol symbol : method setValue(java.lang.Object&java.io.Serializable&java.lang.Comparable<? extends java.lang.Object&java.io.Serializable&java.lang.Comparable<?>>) I think compiler uses the nearest common superclass

java conditional operator and different types

别等时光非礼了梦想. 提交于 2020-11-25 02:16:42
问题 I have two methods in the Item Class: public void setValue(String v); public void setValue(Double v); and I want to use Conditional Operator to setVAlue in another class: String str = ... Double dbl = ... item.setValue((condition) ? str : dbl); but compiler says: cannot find symbol symbol : method setValue(java.lang.Object&java.io.Serializable&java.lang.Comparable<? extends java.lang.Object&java.io.Serializable&java.lang.Comparable<?>>) I think compiler uses the nearest common superclass

java conditional operator and different types

自古美人都是妖i 提交于 2020-11-25 02:15:40
问题 I have two methods in the Item Class: public void setValue(String v); public void setValue(Double v); and I want to use Conditional Operator to setVAlue in another class: String str = ... Double dbl = ... item.setValue((condition) ? str : dbl); but compiler says: cannot find symbol symbol : method setValue(java.lang.Object&java.io.Serializable&java.lang.Comparable<? extends java.lang.Object&java.io.Serializable&java.lang.Comparable<?>>) I think compiler uses the nearest common superclass