Parsing JSON in PHP “stdClass could not be converted to string” error

问题

I had this string:

{\"lat\":37.790388261934424,\"lng\":-122.46047996826172},{\"lat\":37.789608231530124,\"lng\":-122.46344112701416}

Then thanks to the help of StackOverflowers, I did this to strip the slashes:

$markers = stripslashes($markers);

Then I tried to add the outside brackets which seemed to be needed by the decode function

$markers = json_decode('['.$markers.']');

Was that the right way to go about it? Then I tried to do this:

foreach($markers as $key => $value) 
{
    $some_string = $some_string.' ( '.$value.' ) ';
}

Which game me this error:

Object of class stdClass could not be converted to string

But what I really need is to extract the lat/lng values into $lat , $lng variables. Could someone suggest to me how to fix the error I am getting and put the values into the variables?

Thanks, Alex

回答1:

Try...

foreach($markers as $marker) 
{
     $some_string .= '('.$marker->lat.','.$marker->lng.')';
}

Result...

(37.7903882619,-122.460479968)(37.7896082315,-122.463441127)

回答2:

foreach($markers as $key => $value) 
{
    // $value is object with lat and lng properties 
    $some_string = $some_string.' ( lat:'.$value->lat.' ) ';
}

回答3:

This was something that puzzled me too, why is json_decode() returning the data encapsulated in objects?

It turns out that all arrays in Javascript are considered objects, hence json_decode() returns them as objects of the PHP stdClass. Try to do print_r() on the $marker to see how it is structured.

回答4:

This here works

var json = JSON.parse(<?php echo "'" . stripslashes($_POST['json']) . "'" ?>);

来源：https://stackoverflow.com/questions/5527436/parsing-json-in-php-stdclass-could-not-be-converted-to-string-error

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