call_user_func(array($this, $method), $par) from parent's constructor?

问题:

class Parent {    public function __construct($method) {     call_user_func(array($this, $method), 1);   }  }  class Child extends Parent {    public function __construct($method) {     parent::__construct($method);   }    protected function call_me_on_construct($par) {      echo $par;   }  } 

Creating instance of $child = new Child("call_me_on_construct"); I want call_me_on_construct method to be called. The problem is Parent's constructor know nothing about $this. What is better way to do it?

Thank you.

回答1:

It knows about $this. The only error in your code is that you use reserved keyword parent

class Ancestor {    public function __construct($method) {     call_user_func(array($this, $method), 1);   }  }  class Child extends Ancestor {    public function __construct($method) {     parent::__construct($method);   }    protected function call_me_on_construct($par) {      echo $par;   }  }  $c = new child("call_me_on_construct"); 

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