We have now started using calc() in css, for setting widths on a result of calculation. For example:
<div id='parent'> <div id='calcWidth'></div> </div> #parent{ width:100px; } #calcWidth{ width:calc(100% - 3px); height:100px; background:red; } I know how calc() works, but I just want to know what is returned in css, in the place of calc(100% - 3px); in the example given above.
Whats my confusion?
In the above example
width:calc(100% - 3px);say the
100%width is actually100px, which will be determined at runtime by css.So the calculated width will be
100px-3px=97px97px and if you convert it to%97%right?
But now, there are two possibilities
97pxis returned, which is set as a width.97%is returned, which is set as a width.
My Question is:
In both cases now the width shall be set to
97px, but what is returned as a result ofwidth:calc(100% - 3px);,97pxOR97%?
you can also see this fiddle: http://jsfiddle.net/8yspnuuw/1/
EDIT: please read
See friends: Take a simple example:
<div class='parent'> <div class='child'> </div> </div> .parent{ width:200px; } .child{ width:20% } I know the width of child will become 160 px when it is rendered. okay! but thats not what is set in css right? css sets it in %, it is just rendered in pixels.
So similarly, using calc, does it return % or pixel
Or to explain my question, read BoltClocks answer, what is the computed value, (and not the used value, i know that is in pixels)