leetcode 20. Valid Parentheses

Given a string containing just the characters '(', ')', '{', '}', '[' and ']', determine if the input string is valid.

An input string is valid if:

1. Open brackets must be closed by the same type of brackets.
2. Open brackets must be closed in the correct order.

Note that an empty string is also considered valid.

Example 1:

Input: "()" Output: true

Example 2:

Input: "()[]{}" Output: true

Example 3:

Input: "(]" Output: false

Example 4:

Input: "([)]" Output: false

Example 5:

Input: "{[]}" Output: true

思路：栈实现

 1 class Solution {  2 public:  3     bool isValid(string s) {  4         stack<char> st;  5         int len = s.length();  6         for (int i = 0; i < len; ++i) {  7             if (!st.empty()) {  8                 if (s[i] == '(' || s[i] == '{' || s[i] == '[') {  9                     st.push(s[i]); 10                 } else if ((s[i] == ')' && st.top() == '(') || 11                            (s[i] == '}' && st.top() == '{') || 12                            (s[i] == ']' && st.top() == '[')) { 13                     st.pop(); 14                 } else { 15                     st.push(s[i]); 16                 } 17             } else { 18                 st.push(s[i]); 19             } 20         } 21         if (st.empty()) 22             return true; 23         else 24             return false; 25     } 26 };

 

来源：博客园

作者：琴影

链接：https://www.cnblogs.com/qinduanyinghua/p/11552957.html