题目链接：https://leetcode-cn.com/explore/interview/card/top-interview-quesitons-in-2018/275/string/1144/
题目描述
编写一个函数，其作用是将输入的字符串反转过来。输入字符串以字符数组 char[] 的形式给出。
不要给另外的数组分配额外的空间，你必须原地修改输入数组、使用 O(1) 的额外空间解决这一问题。
你可以假设数组中的所有字符都是 ASCII 码表中的可打印字符。
示例 1：
输入：["h","e","l","l","o"] 输出：["o","l","l","e","h"] 示例 2：
输入：["H","a","n","n","a","h"] 输出：["h","a","n","n","a","H"] 代码
class Solution { public: void reverseString(vector<char>& s) { if(s.size()<=1) return; int begin = 0; int end = s.size() -1; while(begin < end){ char tmp = s[begin]; s[begin] = s[end]; s[end] = tmp; ++ begin; -- end; } } }; 文章来源: https://blog.csdn.net/zjwreal/article/details/89707450