Lintcode 37. Reverse 3-digit Integer 反转一个3位整数

class Solution:
    """
    @param number: A 3-digit number.
    @return: Reversed number.
    """
    def reverseInteger(self, number):
        return int(str(number)[::-1])
    
if __name__ == "__main__":
    a = input("输入3位整数: ")
    so = Solution()
    print(so.reverseInteger(a))

测试结果

来源：https://www.cnblogs.com/yongestcat/p/11850891.html