# 列表:有序,元素可以被修改 # 列表 # list # li = [111,22,33,44] # 元组:元素不可被修改,不能被增加或者删除 # ps: # tuple # tu = (11,22,33,44,22,22) # print(tu.count(22)) #获取指定元素在元组中出现的次数 # print(tu.index(22)) ########### 深灰魔法 ########### # 1. 书写格式 # 一般写元组的时候，推荐在最后加入 , # 元素不可被修改，不能被增加或者删除 # tu = (111,"raito",(11,22),[(33,44)],True,33,44,) # 2. 索引 # v = tu[0] # print(v) # 3. 切片 # v = tu[0:2] # print(v) # 4. 可以被for循环，可迭代对象 # for item in tu: # print(item) # 5. 转换 # s = "asdfasdf0" # li = ["asdf","asdfasdf"] # tu = ("asdf","asdf") # # v = tuple(s) # print(v) # v = tuple(li) # print(v) # v = list(tu) # print(v) # v = "_".join(tu) # print(v) # li = ["asdf","asdfasdf"] # li.extend((11,22,33,)) # print(li) # 6.元组的一级元素不可修改/删除/增加 # tu = (111,"raitorei",(3,4),[(1,2)],True,7,11,) # 元组，有序。 # v = tu[3][0][0] # print(v) # v=tu[3] # print(v) # tu[3][0] = 567 # print(tu)
来源：博客园
作者：星空月零
链接：https://www.cnblogs.com/raitorei/p/11626280.html