给定一个二叉树,返回它的 前序 遍历。
示例:
输入: [1,null,2,3]
1
2
/
3
输出: [1,2,3]
# Definition for a binary tree node. # class TreeNode: # def __init__(self, x): # self.val = x # self.left = None # self.right = None class Solution: def preorderTraversal(self, root): """ :type root: TreeNode :rtype: List[int] """ result=[] if(root==None): return result stack=list() stack.append(root) while(len(stack)!=0): top=stack.pop() if(top.right!=None): stack.append(top.right) if(top.left!=None): stack.append(top.left) result.append(top.val) return result