问题
I understand that one technique for dealing with spaces in filenames is to enclose the file name with single quotes: "'".
Why is it that the following code called, "echo.sh" works on a directory containing filenames with spaces, but the program "ls.sh" does Not work, where the only difference is 'echo' replaced with 'ls'?
echo.sh
#!/bin/sh
for f in *
do
echo "'$f'"
done
Produces:
'a b c'
'd e f'
'echo.sh'
'ls.sh'
But, "ls.sh" fails:
#!/bin/sh
for f in *
do
ls "'$f'"
done
Produces:
ls: cannot access 'a b c': No such file or directory
ls: cannot access 'd e f': No such file or directory
ls: cannot access 'echo.sh': No such file or directory
ls: cannot access 'ls.sh': No such file or directory
回答1:
you're actually adding redundant "'" (which your echo invocation shows)
try this:
#!/bin/sh
for f in *
do
ls "$f"
done
回答2:
change the following line from
ls "'$f'"
into
ls "$f"
回答3:
Taking a closer look at the output of your echo.sh script you might notice the result is probably not quite the one you expected as every line printed is surrounded by '
characters like:
'file-1'
'file-2'
and so on.
Files with that names really don't exist on your system. Using them with ls
ls will try to look up a file named 'file-1'
instead of file-1
and a file with such a name just doesn't exist.
In your example you just added one pair of '
s too much. A single pair of double quotes"
is enough to take care of spaces that might contained in the file names:
#!/bin/sh
for f in *
do
ls "$f"
done
Will work pretty fine even with file names containing spaces. The problem you are trying to avoid would only arise if you didn't use the double quotes around $f
like this:
#!/bin/sh
for f in *
do
ls $f # you might get into trouble here
done
回答4:
What about this ? =)
#!/bin/sh
for f in *; do
printf -- '%s\n' "$f"
done
来源:https://stackoverflow.com/questions/15511006/shell-script-issue-with-filenames-containing-spaces