Javascript: closure of loop?

两盒软妹~` 提交于 2019-11-26 13:47:48
for(var i = 0; i < 10; i++) {
    (function(i) {
        createButton(function() { alert("button " + i + " pressed"); });
    })(i);
}

Note that JSLint doesn't like this pattern. It throws "Don't make functions within a loop.".

Live demo: http://jsfiddle.net/simevidas/ZKeXX/

One solution, if you're coding for a browser that uses JavaScript 1.7 or higher, is to use the let keyword:

for(var i = 0; i < 10; ++i) {
    let index = i;
    createButton(x, y, function() { alert("button " + index + " pressed"); }
}

From the MDC Doc Center:

The let keyword causes the item variable to be created with block level scope, causing a new reference to be created for each iteration of the for loop. This means that a separate variable is captured for each closure, solving the problem caused by the shared environment.

Check out the MDC Doc Center for the traditional approach (creating another closure).

Peter Davis

Create a new scope for the closure by executing another function:

for(var i = 0; i < 10; ++i) {
    createButton(x,y, function(value) { return function() { alert(...); }; }(i));
}

http://www.mennovanslooten.nl/blog/post/62

You need to put the closure into a separate function.

for(var dontUse = 0; dontUse < 10; ++dontUse) {
    (function(i) {
        createButton(x, y, function() { alert("button " + i + " pressed"); }
    })(dontUse);
}

Thise code creates an anonymous function that takes i as a parameter for each iteration of the loop.
Since this anonymous function has a separate i parameter for each iteration, it fixes the problem.

This is equivalent to

function createIndexedButton(i) {
    createButton(x, y, function() { alert("button " + i + " pressed"); }
}

for(var i = 0; i < 10; ++i) {
    createIndexedButton(i);
}
for(var i = 0; i < 10; ++i) {
    createButton(x, y, (function(n) {
        return function() {
            alert("button " + n + " pressed");
        }
    }(i));
}

The anonymous function on the outside is automatically invoked and creates a new closure with n in its scope, where that takes the then current value of i each time it's invoked.

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