get filename from url path in R

≡放荡痞女 提交于 2019-12-01 17:54:47

There's a function for that...

basename(path)
[1] "fooXbar.xls"

@SimonO101 has the most robust answer IMO, but some other options:

Since regular expressions are greedy, you can use that to your advantage

sub('.*/', '', path)
# [1] "fooXbar.xls"

Also, you shouldn't need the [] around the / in your strsplit.

> tail(strsplit(path,"/")[[1]],1)
[1] "fooXbar.xls"
标签
易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!