问题
I'm pretty new to Ruby and Rails but even after searching stack overflow and google I couldn't find an answer to this.
I've got a simple Ruby shorthand if statement that should return an integer like so:
# in the context of this erb document `amount` is defined as 5.
@c = ( defined? amount ? amount : r( 1,4 ) )
r() is a custom helper function that returns a random number between in this case 1 and 4.
The way I intend this to work is that if amount is defined, then use the number defined as amount, else generate a random number between 1 and 4 and use that instead.
When printing out @c however Ruby outputs expression rather than a number.
What do I have to do to get this working as I intended and what am I doing wrong?
Many thanks for reading!
回答1:
defined? is binding to amount ? amount : r(1,4) so it is equivalent to:
defined?(amount ? amount : r(1,4))
You probably want:
defined?(amount) ? amount : r(1,4)
Actually, odds are that amount || r(1,4), or amount.nil? ? r(1,4) : amount would better match what you want, since I think you don't want this:
1.9.3p194 :001 > defined?(amount) => nil 1.9.3p194 :002 > amount = nil => nil 1.9.3p194 :003 > defined?(amount) => "local-variable"
...in which case @c would be nil - the value of the defined variable.
回答2:
Use the || operator in this case:
@c = amount || r (1,4)
In your code, the defined? method operates on amount ? amount : r( 1,4 ) instead of just on amount as you intended. Also, the defined? operator probably doesn't do what you expect, have a look at this blog entry to get an idea.
回答3:
You're looking for the null coalescing operator. Try this:
@c = amount || r(1,4)
This code will assign amount to @c if amount is defined. If not it will assign the result of r(1,4) to @c.
http://eddiema.ca/2010/07/07/the-null-coalescing-operator-c-ruby-js-python/
来源：https://stackoverflow.com/questions/10467523/ternary-expression-with-defined-returns-expression-instead-of-value