Which has more priority: || or && or ==

Question

I have this expression:

y[i] = ( z[i] == a && b || c )

Which of these elements (&&, ||, ==) have the priority?

Can you please show the order of operations with brackets?

Answer 1

First ==, then &&, then ||.

Your expression will be evaluated as y[i] = (((z[i] == a) && b) || c).

https://docs.oracle.com/javase/tutorial/java/nutsandbolts/operators.html

Answer 2

The priority list:

1. ==
   
2. &&
   
3. ||
   

Answer 3

This would be :

y[i] = ((( (z[i]) == a )&& b) || c)

ref: http://introcs.cs.princeton.edu/java/11precedence/

Answer 4

The actual expression is evaluated as

y[i] = ( ((z[i] == a) && b) || c )

You probably want to look here for more info on operator precedence. https://docs.oracle.com/javase/tutorial/java/nutsandbolts/operators.html

Answer 5

Here's the full list of ALL OPERATORS:

Full list of operators in Java

Got it from "Java ist auch eine Insel" = "Java is also an island"