SQL Order By Count | 易学教程

问题

If I have a table and data like this:

ID |  Name  |  Group   

1    Apple     A    

2    Boy       A

3    Cat       B

4    Dog       C

5    Elep      C

6    Fish      C

and I wish to order it according to the total of Group from smallest to largest value, such as : A - 2 records , B - 1 record , C - 3 records , so it will become:

3    Cat       B

1    Apple     A    

2    Boy       A

4    Dog       C

5    Elep      C

6    Fish      C

I tried

    $sql = \"SELECT ID,Name FROM table ORDER BY COUNT(Group)\";

but it just returns one result for me.

Are there any hints? Thank you.

回答1:

You need to aggregate the data first, this can be done using the GROUP BY clause:

SELECT Group, COUNT(*)
FROM table
GROUP BY Group
ORDER BY COUNT(*) DESC

The DESC keyword allows you to show the highest count first, ORDER BY by default orders in ascending order which would show the lowest count first.

回答2:

Try :

SELECT count(*),group FROM table GROUP BY group ORDER BY group

to order by count descending do

SELECT count(*),group FROM table GROUP BY group ORDER BY count(*) DESC

This will group the results by the group column returning the group and the count and will return the order in group order

回答3:

SELECT Group, COUNT(*) FROM table GROUP BY Group ORDER BY Group

or to order by the count

SELECT Group, COUNT(*) AS count FROM table GROUP BY Group ORDER BY count DESC

回答4:

SELECT * FROM table 
group by `Group`
ORDER BY COUNT(Group)

回答5:

...none of the other answers seem to do what the asker asked.

For table named 'things' with column 'group':

SELECT
  things.*, counter.count
FROM
  things
LEFT JOIN (
  SELECT
    things.group, count(things.group) as count
  FROM
    things
  GROUP BY
    things.group
) counter ON counter.group = things.group
ORDER BY
  counter.count ASC;

which gives:

id | name  | group | count 
---------------------------
3  | Cat   | B     | 1
1  | Apple | A     | 2
2  | Boy   | A     | 2
4  | Dog   | C     | 3
5  | Elep  | C     | 3
6  | Fish  | C     | 3

回答6:

Try using below Query:

SELECT
    GROUP,
    COUNT(*) AS Total_Count
FROM
    TABLE
GROUP BY
    GROUP
ORDER BY
    Total_Count DESC

回答7:

Below gives me opposite of what you have. (Notice Group column)

SELECT
    *
FROM
    myTable
GROUP BY
    Group_value,
    ID
ORDER BY
    count(Group_value)

Let me know if this is fine with you...

I am trying to get what you want too...

回答8:

Q. List the name of each show, and the number of different times it has been held. List the show which has been held most often first.

event_id show_id event_name judge_id
0101    01  Dressage        01
0102    01  Jumping         02
0103    01  Led in          01
0201    02  Led in          02
0301    03  Led in          01
0401    04  Dressage        04
0501    05  Dressage        01
0502    05  Flag and Pole   02

Ans:

select event_name, count(show_id) as held_times from event 
group by event_name 
order by count(show_id) desc

来源：https://stackoverflow.com/questions/9545637/sql-order-by-count

标签

mysql

database

sql-order-by