Inheriting from a namedtuple base class - Python

你。 提交于 2019-12-01 14:58:56

You can, but you have to override __new__ which is called implicitly before __init__:

class Z(X):
  def __new__(cls, a, b, c, d):
    self = super(Z, cls).__new__(cls, a, b, c)
    self.d = d
    return self

>>> z = Z(1, 2, 3, 4)
>>> z
Z(a=1, b=2, c=3)
>>> z.d
4

But d will be just an independent attribute!

>>> list(z)
[1, 2, 3]

I think you can achieve what you want by including all of the fields in the original named tuple, then adjusting the number of arguments using __new__ as schwobaseggl suggests above. For instance, to address max's case, where some of the input values are to be calculated rather than supplied directly, the following works:

from collections import namedtuple

class A(namedtuple('A', 'a b c computed_value')):
    def __new__(cls, a, b, c):
        computed_value = (a + b + c)
        return super(A, cls).__new__(cls, a, b, c, computed_value)

>>> A(1,2,3)
A(a=1, b=2, c=3, computed_value=6)

I came here with the exact same problem, just two years later.
I personally thought that the @property decorator would fit in here better:

from collections import namedtuple

class Base:
    @property
    def computed_value(self):
        return self.a + self.b + self.c

# inherits from Base
class A(Base, namedtuple('A', 'a b c')):
    pass

cls = A(1, 2, 3)
print(cls.computed_value)
# 6
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