SPARQL query help needed for DBpedia all programming language details

独自空忆成欢 提交于 2019-12-01 14:23:16

As @AKSW said, something like --

SELECT                                                      ?pl 
                                                            ?abstract
       ( group_concat ( ?_influenced; separator="; " )   AS ?influenced )
       ( group_concat ( ?_influencedBy; separator="; " ) AS ?influencedBy ) 
WHERE
  { ?pl  dbo:abstract      ?abstract . 
    ?pl  dbo:influenced    ?_influenced . 
    ?pl  dbo:influencedBy  ?_influencedBy . 
    ?pl  rdf:type          dbo:ProgrammingLanguage . 
    FILTER ( LANG ( ?abstract ) = 'en' ) . 
  } 
GROUP BY ?pl ?abstract

Edit to Add

To get the ?pl_label (and I'm guessing, the ?_influenced_label and ?_influencedBy_label) you now say you want, you will need (and/or want) to tweak things a bit...

SELECT                                                            ?pl 
                                                                  ?pl_label
       ( group_concat ( DISTINCT ?_influenced_label; separator="; " )   AS ?influenced )
       ( group_concat ( DISTINCT ?_influencedBy_label; separator="; " ) AS ?influencedBy ) 
                                                                  ?abstract
WHERE
  { ?pl             rdf:type          dbo:ProgrammingLanguage .
    ?pl             dbo:abstract      ?abstract . 
                    FILTER ( LANG ( ?abstract ) = 'en' ) 
    ?pl             rdfs:label         ?pl_label
                    FILTER ( LANG ( ?pl_label ) = 'en' ) .
    ?pl             dbo:influenced    ?_influenced . 
    ?_influenced    rdfs:label         ?_influenced_label
                    FILTER ( LANG ( ?_influenced_label ) = 'en' ) .
    ?pl             dbo:influencedBy  ?_influencedBy . 
    ?_influencedBy  rdfs:label         ?_influencedBy_label
                    FILTER ( LANG ( ?_influencedBy_label ) = 'en' ) .
          } 
GROUP BY ?pl ?pl_label ?abstract
标签
易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!