I'm extremely stuck at the moment as I am trying to figure out how to calculate the probability from my glm output in R. I know the data is very insignificant but I would really love to be shown how to get the probability from an output like this. I was thinking of trying inv.logit() but didn't know what variables to put within the brackets.
The data is from occupancy study. I'm assessing the success of a hair trap method versus a camera trap in detecting 3 species (red squirrel, pine marten and invasive grey squirrel). I wanted to see what affected detection (or non detection) of the various species. One hypotheses was the detection of another focal species at the site would affect the detectability of red squirrel. Given that pine marten is a predator of the red squirrel and that the grey squirrel is a competitor, the presence of those two species at a site might affect the detectability of the red squirrel.
Would this show the probability? inv.logit(-1.14 - 0.1322 * nonRS events)
glm(formula = RS_sticky ~ NonRSevents_before1stRS, family = binomial(link = "logit"), data = data)
Deviance Residuals:
Min 1Q Median 3Q Max
-0.7432 -0.7432 -0.7222 -0.3739 2.0361
Coefficients:
Estimate Std. Error z value Pr(>|z|)
(Intercept) -1.1455 0.4677 -2.449 0.0143 *
NonRSevents_before1stRS -0.1322 0.1658 -0.797 0.4255
---
Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1
(Dispersion parameter for binomial family taken to be 1)
Null deviance: 34.575 on 33 degrees of freedom
Residual deviance: 33.736 on 32 degrees of freedom
(1 observation deleted due to missingness)
AIC: 37.736
Number of Fisher Scoring iterations: 5*
If you want to predict the probability of response for a specified set of values of the predictor variable:
pframe <- data.frame(NonRSevents_before1stRS=4)
predict(fitted_model, newdata=pframe, type="response")
where fitted_model is the result of your glm() fit, which you stored in a variable. You may not be familiar with the R approach to statistical analysis, which is to store the fitted model as an object/in a variable, then apply different methods to it (summary(), plot(), predict(), residuals(), ...)
- This is obviously only a made-up example: I don't know if 4 is a reasonable value for the
NonRSevents_before1stRSvariable) - you can specify more different values to do predictions for at the same time (
data.frame(NonRSevents_before1stRS=c(4,5,6,7,8))) - if you have multiple predictors, you have to specify some value for every predictor for every prediction, e.g.
data.frame(x=4:8,y=mean(orig_data$y), ...)
If you want the predicted probabilities for the observations in your original data set, just predict(fitted_model, type="response")
You're correct that inv.logit() (from a bunch of different packages, don't know which you're using) or plogis() (from base R, essentially the same) will translate from the logit or log-odds scale to the probability scale, so
plogis(predict(fitted_model))
would also work (predict provides predictions on the link-function [in this case logit/log-odds] scale by default).
The dependent variable in a logistic regression is a log odds ratio. We'll illustrate how to interpret the coefficients with the space shuttle autolander data from the MASS package.
After loading the data, we'll create a binary dependent variable where:
1 = autolander used,
0 = autolander not used.
We will also create a binary independent variable for shuttle stability:
1 = stable positioning
0 = unstable positioning.
Then, we'll run glm() with family=binomial(link="logit"). Since the coefficients are log odds ratios, we'll exponentiate them to turn them back into odds ratios.
library(MASS)
str(shuttle)
shuttle$stable <- 0
shuttle[shuttle$stability =="stab","stable"] <- 1
shuttle$auto <- 0
shuttle[shuttle$use =="auto","auto"] <- 1
fit <- glm(use ~ factor(stable),family=binomial(link = "logit"),data=shuttle) # specifies base as unstable
summary(fit)
exp(fit$coefficients)
...and the output:
> fit <- glm(use ~ factor(stable),family=binomial(link = "logit"),data=shuttle) # specifies base as unstable
>
> summary(fit)
Call:
glm(formula = use ~ factor(stable), family = binomial(link = "logit"),
data = shuttle)
Deviance Residuals:
Min 1Q Median 3Q Max
-1.1774 -1.0118 -0.9566 1.1774 1.4155
Coefficients:
Estimate Std. Error z value Pr(>|z|)
(Intercept) 4.747e-15 1.768e-01 0.000 1.0000
factor(stable)1 -5.443e-01 2.547e-01 -2.137 0.0326 *
---
Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1
(Dispersion parameter for binomial family taken to be 1)
Null deviance: 350.36 on 255 degrees of freedom
Residual deviance: 345.75 on 254 degrees of freedom
AIC: 349.75
Number of Fisher Scoring iterations: 4
> exp(fit$coefficients)
(Intercept) factor(stable)1
1.0000000 0.5802469
>
The intercept of 0 is the log odds for unstable, and the coefficient of -.5443 is the log odds for stable. After exponentiating the coefficients, we observe that the odds of autolander use under the condition of an unstable shuttle 1.0, and are multiplied by .58 if the shuttle is stable. This means that the autolander is less likely to be used if the shuttle has stable positioning.
Calculating probability of autolander use
We can do this in two ways. First, the manual approach: exponentiate the coefficients and convert the odds to probabilities using the following equation.
p = odds / (1 + odds)
With the shuttle autolander data it works as follows.
# convert intercept to probability
odds_i <- exp(fit$coefficients[1])
odds_i / (1 + odds_i)
# convert stable="stable" to probability
odds_p <- exp(fit$coefficients[1]) * exp(fit$coefficients[2])
odds_p / (1 + odds_p)
...and the output:
> # convert intercept to probability
> odds_i <- exp(fit$coefficients[1])
> odds_i / (1 + odds_i)
(Intercept)
0.5
> # convert stable="stable" to probability
> odds_p <- exp(fit$coefficients[1]) * exp(fit$coefficients[2])
> odds_p / (1 + odds_p)
(Intercept)
0.3671875
>
The probability of autolander use when a shuttle is unstable is 0.5, and decreases to 0.37 when the shuttle is stable.
The second approach to generate probabilities is to use the predict() function.
# convert to probabilities with the predict() function
predict(fit,data.frame(stable="0"),type="response")
predict(fit,data.frame(stable="1"),type="response")
Note that the output matches the manually calculated probabilities.
> # convert to probabilities with the predict() function
> predict(fit,data.frame(stable="0"),type="response")
1
0.5
> predict(fit,data.frame(stable="1"),type="response")
1
0.3671875
>
Applying this to the OP data
We can apply these steps to the glm() output from the OP as follows.
coefficients <- c(-1.1455,-0.1322)
exp(coefficients)
odds_i <- exp(coefficients[1])
odds_i / (1 + odds_i)
# convert nonRSEvents = 1 to probability
odds_p <- exp(coefficients[1]) * exp(coefficients[2])
odds_p / (1 + odds_p)
# simulate up to 10 nonRSEvents prior to RS
coef_df <- data.frame(nonRSEvents=0:10,
intercept=rep(-1.1455,11),
nonRSEventSlope=rep(-0.1322,11))
coef_df$nonRSEventValue <- coef_df$nonRSEventSlope *
coef_df$nonRSEvents
coef_df$intercept_exp <- exp(coef_df$intercept)
coef_df$slope_exp <- exp(coef_df$nonRSEventValue)
coef_df$odds <- coef_df$intercept_exp * coef_df$slope_exp
coef_df$probability <- coef_df$odds / (1 + coef_df$odds)
# print the odds & probabilities by number of nonRSEvents
coef_df[,c(1,7:8)]
...and the final output.
> coef_df[,c(1,7:8)]
nonRSEvents odds probability
1 0 0.31806 0.24131
2 1 0.27868 0.21794
3 2 0.24417 0.19625
4 3 0.21393 0.17623
5 4 0.18744 0.15785
6 5 0.16423 0.14106
7 6 0.14389 0.12579
8 7 0.12607 0.11196
9 8 0.11046 0.09947
10 9 0.09678 0.08824
11 10 0.08480 0.07817
>
来源：https://stackoverflow.com/questions/48131237/how-to-get-probability-from-glm-output