Different Java Scanner for input of different types

依然范特西╮ 提交于 2019-12-01 12:25:54

@skiwi is right about only using one Scanner, so you're doing that right. The reason it doesn't work is that nextInt() consumes all characters that make up the integer, but it does not touch the end-of-line character. So when nextLine() is called, it sees that there are no characters before the end-of-line character, so it thinks that an empty line was entered, and you get an empty String back. However, nextLine() does consume the end-of-line character, so if you call sc.nextLine(); once before you do name = sc.nextLine();, it should work.

You should use only one Scanner instance per object that you are scanning. In this case you are reading from the System.in, so opening two scanners on the same them concurrently does not even make sense.

So you definately want to go with your first option, then the question comes, what is wrong with it:

Well, you ask for sc.nextInt(), an integer, and a name rarely is an integer. You are most likely looking for either name = sc.next() for one word or for name = sc.nextLine() for a whole sentence (until the enter key has been pressed).

Also be aware that after sc.nextInt(), actually after any sc.next***(), you need to press Enter.

You were not given a chance to enter the name because nextInt() doesn't read the new-line character '\n' (inputted by user after pressing Enter), whereas nextLine() does. So as soon as you call name = sc.nextLine();, it will just read the '\n' character that the nextInt() didn't read already.

Definitely do not create a new Scanner if the Scanner if you're scanning the same thing (like System.in) - only change Scanners if you are scanning something else, like different files or something.

To get your code working (with only one Scanner instance), use this:

int age = 0;
String name;
Scanner sc = new Scanner(System.in);

System.out.print("Enter Age: ");
age = sc.nextInt();
System.out.print("Enter Name: ");

sc.nextLine(); // "dispose" of the '\n' character
               // so that it is not recorded by the next line

name = sc.nextLine();

// print your findings
System.out.println("------\nAge: " + age + "\nName: " + name);

Example input/output:

Enter Age: 17
Enter Name: Michael
------
Age: 17
Name: Michael
chahboune Imad

You can also use:

name = sc.next();

This must work perfectly. I tested it out.

int age=0;
String name;
Scanner sc = new Scanner(System.in);

System.out.print("Enter Age: ");
age = sc.nextInt();
System.out.print("Enter Name: ");
name= sc.nextLine();
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