RxSwift - how to chain observables sequentially

回眸只為那壹抹淺笑 提交于 2019-12-01 10:29:26
Maxim Volgin

Operator .concatMap() guarantees that order remains intact, as opposed to .flatMap()

i.e.

Observable.from([1,2,3,4,5]).concatMap( /* your request code */ )

UPDATE

let source = Observable.from([1,2,3,4,5])
let trigger = BehaviorSubject<Int>(value: 0)
let feed = Observable.zip(source, trigger) { return $0.0 }

feed.concatMap {
    /* your request code */
    trigger.onNext(0) // possibly in .onComplete of the service call
}
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