AngularJS: Is there a better way to achieve this than the one specified?

I use a template that generates a Bootstrap tab layout. Like below:

<div class="a">
    <ul class="nav nav-bar nav-stacked" role="tabs">
        <li><a href="#home"></a></li>
        ...
    </ul>
    <div class="tab-content">
        <div id="home">abc</div>
        ...
    </div>
</div>

Now this is pretty simple and straightforward tab navigation that can be hardcoded and achieved.

I have a dynamic ng-repeat on the ul's li and the tab-content's divs.

The JSON that I get from the REST service is something that contains the data for the tabs and the content to be displayed inside the tab-content within a single object. For eg:

{
    "0": "a": [{ // a- tab data
                   "0": "abc", // abc - data to be displayed inside the tab-content
                   "1": "xyz"
               }]
  ...
}

With such a JSON hierarchy, I basically need to ng-repeat twice. Once for the ul li and once for the tab-content as each object of the tab contains the data related to it.

So what I have done so far is:

<div class="a">
    <ul class="nav nav-bar nav-stacked" role="tabs">
        <li ng-repeat="foo in data"><a href="#home">{{foo.name}}</a></li>
        ...
    </ul>
    <div class="tab-content">
        <div id="home" ng-repeat="foo in data">
            <p ng-repeat="f in foo.desc">{{f}}</p>
        </div>
        ...
    </div>
</div>

EDIT: So my question is, is there a smarter way to achieve this using a single ng-repeat rather than doing "foo in data" twice?

Sorry if my question isn't clear.

Use ng-include with $templateCache rather than ng-repeat. For example:

var app = angular.module('foo', []);

function foo($templateCache)
  {
  var model = 
    {"data":
     [
       {"name": "Stack",
        "desc": ["Exchange", "Overflow"]
       }
     ]
    },
    cursor, i, bar = baz = "";
  
  for (i = 0; i < model.data.length; i++)
  	{
    bar = bar.concat("<li>", model.data[i].name,"</li>");
    baz = baz.concat("<li>", model.data[i].desc.join().replace(/,/g,"</li><li>") );
    }
  
  $templateCache.put('name', bar);
  $templateCache.put('desc', baz);      
  }

app.run(foo);

<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>
<div ng-app="foo">
  <ul ng-include="'name'"></ul>
  <ul ng-include="'desc'"></ul>
</div>

References

来源：https://stackoverflow.com/questions/29015493/angularjs-is-there-a-better-way-to-achieve-this-than-the-one-specified

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