Warning : filesize function failing to operate [closed]

问题

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Closed 7 years ago.

The Following Code:

<?php
$filevar = "/images/staunton/{$options_item['base_var']}.gif";

if(filesize($filevar) > 1616){
    $setstatus = "enabled";
}
else{
    $setstatus = "disabled";
}       
?>

Results in:

Warning: filesize() [function.filesize]: stat failed for /images/staunton/3-25.gif in [Originating PHPFILE(Edited)] on line 24

The Path is the correct file.... my hosting server is running php 5.2 - is this a synax error? I've been looking at similar code and it seems to look correct.

回答1:

Instead of this:

$filevar = "/images/staunton/{$options_item['base_var']}.gif";

you probably want:

$filevar = $_SERVER["DOCUMENT_ROOT"] . "/images/staunton/{$options_item['base_var']}.gif";

because you probably was confusing the relative path of your image inside the document root of your page vs the absolute path of the image in the filesystem.

Try it and comment back.

来源：https://stackoverflow.com/questions/12498895/warning-filesize-function-failing-to-operate