How to convert yuy2 to a BITMAP in C++

守給你的承諾、 提交于 2019-12-01 05:19:54

Using the information from the Microsoft link in the question:

for (int i = 0;  i < width/2;  ++i)
{
    int y0 = ptrIn[0];
    int u0 = ptrIn[1];
    int y1 = ptrIn[2];
    int v0 = ptrIn[3];
    ptrIn += 4;
    int c = y0 - 16;
    int d = u0 - 128;
    int e = v0 - 128;
    ptrOut[0] = clip(( 298 * c + 516 * d + 128) >> 8); // blue
    ptrOut[1] = clip(( 298 * c - 100 * d - 208 * e + 128) >> 8); // green
    ptrOut[2] = clip(( 298 * c + 409 * e + 128) >> 8); // red
    c = y1 - 16;
    ptrOut[3] = clip(( 298 * c + 516 * d + 128) >> 8); // blue
    ptrOut[4] = clip(( 298 * c - 100 * d - 208 * e + 128) >> 8); // green
    ptrOut[5] = clip(( 298 * c + 409 * e + 128) >> 8); // red
    ptrOut += 6;
}

This formula worked:

int C = luma - 16;
int D = cr - 128;
int E = cb - 128;
r = (298*C+409*E+128)/256;
g = (298*C-100*D-208*E+128)/256;
b = (298*C+516*D+128)/256;

I got this from a matlab example.

The gotcha is: in memory, Windows bitmaps aren't RGB, they are BGR. If you are writing to a memory buffer, you need to do something like this:

rgbbuffer[rgbindex] = (char)b;
rgbbuffer[rgbindex + 1] = (char)g;
rgbbuffer[rgbindex + 2] = (char)r;

If you were already using DirectShow to get video data out of the security camera, then you could simply add the "Color Space Converter Filter" to your DirectShow graph. But if you aren't using DirectShow already (it sounds like you're not) then it will be much, much simpler to just convert the data to RGB yourself using the formulas that Daniel linked to. Adding DirectShow to a project is very complicated.

You will have to write your own converter. GDI+ doesn't know how to deal with YUY2 bitmaps.

Look here.

Please note that 2 pixels share same color values and have different luminance values.

Here are some formulas to help you write your converter.

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