Aggregate all dataframe row pair combinations using pandas

问题

I use python pandas to perform grouping and aggregation across data frames, but I would like to now perform specific pairwise aggregation of rows (n choose 2, statistical combination). Here is the example data, where I would like to look at all pairs of genes in [mygenes]:

import pandas
import itertools

mygenes=['ABC1', 'ABC2', 'ABC3', 'ABC4']

df = pandas.DataFrame({'Gene' : ['ABC1', 'ABC2', 'ABC3', 'ABC4','ABC5'],
                       'case1'   : [0,1,1,0,0],
                       'case2'   : [1,1,1,0,1],
                       'control1':[0,0,1,1,1],
                       'control2':[1,0,0,1,0] })
>>> df
   Gene  case1  case2  control1  control2
0  ABC1      0      1         0         1
1  ABC2      1      1         0         0
2  ABC3      1      1         1         0
3  ABC4      0      0         1         1
4  ABC5      0      1         1         0

The final product should look like this (applying np.sum by default is fine):

                 case1    case2    control1    control2
'ABC1', 'ABC2'    1         2         0            1
'ABC1', 'ABC3'    1         2         1            1
'ABC1', 'ABC4'    0         1         1            2
'ABC2', 'ABC3'    2         2         1            0
'ABC2', 'ABC4'    1         1         1            1
'ABC3', 'ABC4'    1         1         2            1

The set of gene pairs can be easily obtained with itertools ($itertools.combinations(mygenes, 2)), but I can't figure out how to perform aggregation of specific rows based on their values. Can anyone advise? Thank you

回答1:

I can't think of a clever vectorized way to do this, but unless performance is a real bottleneck I tend to use the simplest thing which makes sense. In this case, I might set_index("Gene") and then use loc to pick out the rows:

>>> df = df.set_index("Gene")
>>> cc = list(combinations(mygenes,2))
>>> out = pd.DataFrame([df.loc[c,:].sum() for c in cc], index=cc)
>>> out
              case1  case2  control1  control2
(ABC1, ABC2)      1      2         0         1
(ABC1, ABC3)      1      2         1         1
(ABC1, ABC4)      0      1         1         2
(ABC2, ABC3)      2      2         1         0
(ABC2, ABC4)      1      1         1         1
(ABC3, ABC4)      1      1         2         1

回答2:

Before going too far, you should keep in mind your data gets big pretty fast. With 5 rows, output will be C(5,2) or 5+4+3+2+1 and so on.

That said, I'd think about doing this in numpy for speed (you may want to add a numpy tag to your question btw). Anyway, this isn't as vectorized as it might be, but ought to be a start at least:

df2 = df.set_index('Gene').loc[mygenes].reset_index()

import math
sz = len(df2)
sz2 = math.factorial(sz) / ( math.factorial(sz-2) * 2 )

Gene = df2['Gene'].tolist()
abc = df2.ix[:,1:].values

import math
arr = np.zeros([sz2,4])
gene2 = []
k = 0

for i in range(sz):
    for j in range(sz):
        if i != j and i < j:
            gene2.append( gene[i] + gene[j] )
            arr[k] = abc[i] + abc[j]
            k += 1

pd.concat( [ pd.DataFrame(gene2), pd.DataFrame(arr) ], axis=1 )
Out[1780]: 
          0  0  1  2  3
0  ABC1ABC2  1  2  0  1
1  ABC1ABC3  1  2  1  1
2  ABC1ABC4  0  1  1  2
3  ABC2ABC3  2  2  1  0
4  ABC2ABC4  1  1  1  1
5  ABC3ABC4  1  1  2  1

Depending on size/speed issues you may need to separate the string and numerical code and vectorize the numerical piece. This code is not likely to scale all that well if your data is big and if it is, that may determine what sort of answer you need (and also may need to think about how you store results).

来源：https://stackoverflow.com/questions/29777702/aggregate-all-dataframe-row-pair-combinations-using-pandas

标签

python

pandas

aggregate

combinations

itertools