问题
I have 2 Django models, ModelA
with an ArrayField
that is used to store a large list of primary key values (possibly 50k+ list)
class ModelA(models.Model):
pk_values = ArrayField(models.IntegerField())
class CustomManager(manager.Manager):
def get_for_index(self, index_id):
qs = self.get_queryset()
obj = ModelA.objects.get(pk=index_id)
return qs.filter(id__in=obj.pk_values)
class ModelB(models.Model):
# [...] some fields
objects = CustomManager()
This works:
qs = ModelB.objects.get_for_index(index_id=1)
However, this would be super slow where "pk_values" is a large list.
So I tried doing raw SQL queries:
class CustomManager(manager.Manager):
def get_for_index(self, index_id):
qs = self.get_queryset()
sql = "SELECT * FROM myapp_model_b JOIN myapp_model_a ON myapp_model_b.id = ANY(myapp_model_a.pk_values) WHERE myapp_model_a.id = '%s'" % index_id
return qs.raw(sql)
But this returns a django.db.models.query.RawQuerySet
instance.
But with this, I cant do things like queryset.values()
afterwards.
How can I convert this to a normal Django queryset?
Is there a better way of doing this?
Docs:
- ArrayField https://docs.djangoproject.com/en/2.0/ref/contrib/postgres/fields/#arrayfield
- Custom Manager https://docs.djangoproject.com/en/2.0/topics/db/managers/#custom-managers-and-model-inheritance
- Raw queries https://docs.djangoproject.com/en/2.0/topics/db/sql/#performing-raw-sql-queries
回答1:
You can use a RawSQL expression:
ModelB.objects.filter(id__in=RawSQL(
'SELECT unnest(a.pk_values) FROM app_modela a WHERE a.id = %s',
[index_id]
))
Alternatively you can reproduce the exact query you have in your question with extra():
ModelB.objects.extra(
tables=['foo_modela'],
where=[
'"app_modelb"."id" = ANY("app_modela"."pk_values")',
'"app_modela"."id" = %s',
],
params=[index_id],
)
回答2:
Update: I got something working using .extra()
class CustomManager(manager.Manager):
def get_for_index(self, index_id):
qs = self.get_queryset()
sql = "myapp_model_b.id IN (SELECT UNNEST(myapp_model_a.pk_values) FROM myapp_model_a WHERE myapp_model_a.id='%s')" % index_id
return qs.extra(where=[sql])
Docs: https://docs.djangoproject.com/en/2.0/ref/models/querysets/#django.db.models.query.QuerySet.extra
来源:https://stackoverflow.com/questions/48288076/convert-django-rawqueryset-to-queryset