问题
I just want to understand following line of code in shell. It is used to get the current working directory. I am aware that $(variable) name return the value inside the variable name, but what is $(command) supposed to return? Does it return the value after executing the command? In that case, we can use ` to execute the command.
CWD=\"$(cd \"$(dirname $0)\"; pwd)\"
Same output can be taken from the following line of code also in different version of shell
DIR=\"$( cd \"$( dirname \"${BASH_SOURCE[0]}\" )\" && pwd )\"
I am unable to understand the meaning of $(cd.. and $(dirname.
Could anybody help me to figure out how this command get executed?
回答1:
Usage of the $ like ${HOME} gives the value of HOME. Usage of the $ like $(echo foo) means run whatever is inside the parentheses in a subshell and return that as the value. In my example, you would get foo since echo will write foo to standard out
回答2:
DIR="$( cd "$( dirname "${BASH_SOURCE[0]}" )" && pwd )"Could anybody help me to figure out how this command get executed?
Let's look at different parts of the command. BASH_SOURCE is a bash array variable containing source filenames. So "${BASH_SOURCE[0]}" would return you the name of the script file.
dirname is a utility provided by GNU coreutils that remove the last component from the filename. Thus if you execute your script by saying bash foo, "$( dirname "${BASH_SOURCE[0]}" )" would return .. If you said bash ../foo, it'd return ..; for bash /some/path/foo it'd return /some/path.
Finally, the entire command "$( cd "$( dirname "${BASH_SOURCE[0]}" )" && pwd )" gets the absolute directory containing the script being invoked.
$(...) allows command substitution, i.e. allows the output of a command to replace the command itself and can be nested.
来源：https://stackoverflow.com/questions/17984958/what-does-it-mean-in-shell-when-we-put-a-command-inside-dollar-sign-and-parenthe