问题
How can I get the number of occurrences for some range based on
A regular expression
2+ conditions; let's say cells that contain "yes" and / or "no"
What I've got for the moment:
COUNTIF(B5:O5; "*yes*")
I tried to use COUNTIF(B5:O5; {"*yes*", "*no*"})
or COUNTIF(B5:O5; "(*yes*)|(*no*)")
, but neither of them worked.
Or, how do I count cells that contain some domain names—yahoo.com, hotmail.com, and gmail.com—using regexp? e.g.:
(\W|^)[\w.+\-]{0,25}@(yahoo|hotmail|gmail)\.com(\W|$)
回答1:
The most pedestrian solution to your problem (tested in Excel and Google Docs) is to simply add the result of several countif
formulas:
=COUNTIF(B5:O5, "*yes*") + COUNTIF(B5:O5, "*no*")
This expression will count the total of cells with "yes" or "no". It will double count a cell with "yesno" or "noyes" since it matches both expressions. You could try to take out the doubles with
=COUNTIF(B5:O5, "*yes*") + COUNTIF(B5:O5, "*no*") - COUNTIF(B5:O5, "*no*yes*") - COUNTIF(B5:O5, "*yes*no*")
But that will still get you in trouble with a string like noyesno
.
However there is a rather clever trick in Google Docs that may just be a hint of the solution you are looking for:
=COUNTA(QUERY(A1:A9, "select A where A matches '(.*yes.*)|(.*no.*)'"))
The QUERY
function is like a mini database thing. In this case it looks at the table in range A1:A9
, and selects only elements in column A where the corresponding element in column A matches
(in the preg regex
sense of the word) the expression that follows - in this case, "anything followed by yes
followed by anything, or anything followed by no
followed by anything". In a simple example I made, this counts a yesnoyes
only once - making it exactly what you were asking for (I think...)
Right now your range B5:O5
is several columns wide, and only one row high; that makes it hard to use the QUERY
trick. Something rather less elegant (but that works regardless of the shape of the range) is this:
=countif(arrayformula(isnumber(find("yes",A1:A9))+isnumber(find("no",A1:A9))),">0")
The sum of the isnumber
functions acts as an element-wise OR
- unfortunately, the regular OR
function doesn't seem to work on individual elements of an array. As before, this finds cells that contain either "yes" or "no", and counts the ones that have either of these strings contained within.
回答2:
This is heavily inspired by Floris's answer. See the comments, in particular. If you TRANSPOSE
the row of items to compare against, QUERY
works fine for horizontal data as well:
=COUNTA(QUERY(TRANSPOSE(B5:O5), "select * where Col1 matches '.*(yes|no).*'"))
As far as I can tell, Col1
is "special" and case sensitive!
回答3:
I've had the same problem, if you don't want to use VBA
, try to add a SUM
to your formula:
=SUM(COUNTIF(B5:O5; {"*yes*", "*no*"}))
回答4:
The easiest way NGix found is to create a custom function for these purposes. They added 2 that work perfectly for them and hope it'll help someone too:
/**
* Count if cell value matches any condition ( supports regexp also )
*/
function countCustomMatchOr(data){
var count = 0;
for(var i=0; i < data.length; i++){
for(var j=0; j<data[i].length; j++){
var cell = data[i][j];
for(var k=1;k<arguments.length;k++){
if(typeof arguments[k] == "number"){
if(arguments[k] == cell) count++;
} else if(cell.toString().match(arguments[k])) count++;
}
}
}
return count;
}
And
/**
* Counts value in data range if matches regular expression
*/
function countCustomRegExp(data, reg, flag){
var rows = data.length, count = 0, re = flag?new RegExp(reg, flag):new RegExp(reg);
for( var i = 0; i < rows; i++){
for( var j = 0; j < data[i].length; j++){
if( data[i][j] != "" && data[i][j].toString().match(re) ){
count++;
}
}
}
return count;
}
In order to use them just apply countCustomRegExp(A2:G3;"yes.*")
or countCustomMatchOr(A2:G3;"yes";"no")
来源:https://stackoverflow.com/questions/18343969/count-number-of-occurrences-based-on-2-conditions-or-regexp